It seems to me that the easy way to do this is to solve your replacement for `x`:
cos(4*x+6).subs(x, (u-3)/2) And if this is just a special case of a more general substitution, you can of course do that solve step with sympy. I can't tell from your question, but this might not be exactly what you wanted. For example, look at (x*cos(4*x+6)).subs(x, (u-3)/2) This will also replace the `x` out front. If you don't want that, you'd need to do an even more complicated version of what Francesco suggests. -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/9e8cacb4-6d6e-4486-9c32-873d0bca8c8e%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
