This dosn't seem reasonable.
Expanding goes on the line Mul(*numer). Mul(*numer, evaluate=False) fixes 
things.

On Friday, March 27, 2015 at 4:31:58 PM UTC+2, Chris Smith wrote:
>
> That seems reasonable since fraction is allowing the expr to rewrite:
>
> >>> 2*e
> 2*(x + 1)/(x - 1)
> >>> fraction(_)
> (2*x + 2, x - 1)
>
>
> On Friday, March 27, 2015 at 4:28:28 AM UTC-5, Paul Royik wrote:
>>
>> Both fraction and as_numer_denom return (2x+2, sin(x)+1) for expression 
>> 2(x+1)/(sin(x)+1), i.e. they rewrite numerator and denominator.
>> I suggest simple fix for fraction: substitute last line return 
>> Mul(*numer), Mul(*denom) with return Mul(*numer, evaluate=False), 
>> Mul(*denom, evaluate=False)
>> For as_numer_denom fix seems harder to implement.
>>
>> Is it possible to change them?
>>
>>
>> On Friday, March 27, 2015 at 1:40:39 AM UTC+2, Aaron Meurer wrote:
>>>
>>> It looks like fraction takes into account assumptions, but on the 
>>> other hand, it doesn't do any rewriting of the expression to combine 
>>> sums of fractions (e.g., fraction(1/x + 1/y) gives (1/x + 1/y, 1), 
>>> whereas (1/x + 1/y).as_numer_denom() gives (x + y, x*y)). 
>>>
>>> Aaron Meurer 
>>>
>>> On Thu, Mar 26, 2015 at 12:09 PM, Paul Royik <[email protected]> 
>>> wrote: 
>>> > I used as_numer_denom earlier and now found fraction. 
>>> > Is there any difference between them? 
>>> > 
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>>

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