On Fri, Apr 10, 2015 at 4:54 PM, Paul Royik <[email protected]> wrote: > Yes. > Is there any way to tell, that t>1 ?
I believe, no. I asked this sometime back. [1] [1] https://groups.google.com/forum/?utm_medium=email&utm_source=footer#!msg/sympy/FC4cCBdKrs0/PJ9WgPzpIhUJ > > On Friday, April 10, 2015 at 5:54:33 AM UTC+3, Chris Smith wrote: >> >> Do you mean something like this? >> >> >>> var('x') >> x >> >>> var('t',nonpositive=True) >> t >> >>> limit(E**((t-1)*x),x,oo) >> 0 >> >> >> >> >> On Thursday, April 9, 2015 at 3:14:17 AM UTC-5, Paul Royik wrote: >>> >>> Hello. >>> I'm trying to calulate limit as x approaches infinity of e^((t-1)x) >>> Naturally, I got Notimplemented error Result depends on the sign of >>> sign(t - 1). >>> >>> My question how can I in general make assumption that this limit is >>> finite? >>> >>> I mean in general, because expression for limit can be arbitrary. >>> Thank you. > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at http://groups.google.com/group/sympy. > To view this discussion on the web visit > https://groups.google.com/d/msgid/sympy/c30545bf-5063-439d-a8eb-ffd981181558%40googlegroups.com. > > For more options, visit https://groups.google.com/d/optout. -- http://echorand.me -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CANODV3%3D7xManjOKjR1XyEL3%2BECGgx-d%2B9urJMB_a3UipmyQgyQ%40mail.gmail.com. For more options, visit https://groups.google.com/d/optout.
