Thank you! On Monday, May 18, 2015 at 3:38:51 AM UTC-7, Chris Smith wrote: > > You could use the attributes of a Triangle object directly (of which there > are many, including area): > > >>> p=Point > >>> A = p(0, 0) > >>> B = p(3, 0) > >>> C = p(3, 3) > >>> Triangle(A,B,C).area > 9/2 > > or simplify your "manual" result: > > >>> simplify(sqrt(-3*sqrt(2)/2 + 3)*sqrt(27*sqrt(2)/4 + S(27)/2)) > 9/2 > > /c > >> >>
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