When chop=True it uses the current precision to replace small arguments 
with an exact zero. If you want to specify the threshold for chopping, pass 
in a value instead of a boolean. The exp(-60) is about 8x10^-27 so if you 
specify chop smaller than that you will not get 0 for the result:

>>> expr.n(chop=1e-27)
0.482830727370613
>>> expr.n(chop=1e-26)
0



On Thursday, May 21, 2015 at 1:49:34 PM UTC-5, Paul Royik wrote:
>
> OK.
> Thank you.
> Could you move it to issues?
>
> On Thursday, May 21, 2015 at 6:45:41 PM UTC+3, Aaron Meurer wrote:
>>
>> I'm guessing chop chops some intermediate expression that is smaller 
>> than the cutoff in this case. It probably should be considered a bug. 
>>
>> Aaron Meurer 
>>
>> On Thu, May 21, 2015 at 8:53 AM, Paul Royik <[email protected]> wrote: 
>> > Nobody could tell how chop works? 
>> > 
>> > On Tuesday, May 5, 2015 at 11:41:24 AM UTC+3, Paul Royik wrote: 
>> >> 
>> >> expr = 
>> >> 
>> 2682469501914725726236807146020965585039500052171867725591732162347*exp(-60)/48648670709168952944186714683693506574127
>>  
>>
>> >> 
>> >> N(expr) outputs 0.482830727370627 
>> >> but 
>> >> N(expr, chop=True) outputs 0 
>> >> 
>> >> In some other expressions chop doesn't make 0. 
>> >> 
>> >> So, how chop works? 
>> > 
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