str(a).rstrip('0') trick won't won't work with complex numbers, like
0.3000000000000+0.50000000000i
On Monday, July 13, 2015 at 7:08:27 PM UTC+3, Vinzent Steinberg wrote:
>
> On Sunday, July 12, 2015 at 6:18:26 PM UTC+2, Paul Royik wrote:
>>
>> Is it possible to set for float precision of 50, but to cut trailing
>> zeros for finite decimals?
>> a=Float('0.5',prec=50)
>> print a/7
>> Output: 0.071428571428571428571428571428571428571428571428571
>>
>>
>> a=Float('0.5',prec=50)
>> print a
>> Output: 0.50000000000000000000000000000000000000000000000000 (but I want
>> a)
>>
>> For latex correct output is 0.5
>> But how to print 0.5 instead of 0.5 with many trailing zeros?
>>
>
> In floating point representation, there is no difference between finite
> and non-finite decimals, so they are printed the same.
> If you want to remove trailing zeros, convert it to a string and strip the
> zeros:
>
> a_without_zeros = str(a).rstrip('0')
>
> Vinzent
>
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