Will do. If I print the expression using str(), I get:
'I_{R_2}(s) == -C_{T}*s*(-R_{1}*V_{in}(s)/(R_{1} + 1/(1/(1/(C_{T}*s +
1/(L_{R}*s + R_{2} + 1/(C_{R}*s))) + 1/(C_{L}*s)) + 1/(L_{L}*s))) + V_{in}(s) -
(-R_{1}*V_{in}(s)/(R_{1} + 1/(1/(1/(C_{T}*s + 1/(L_{R}*s + R_{2} +
1/(C_{R}*s))) + 1/(C_{L}*s)) + 1/(L_{L}*s))) + V_{in}(s))/(C_{L}*s*(1/(C_{T}*s
+ 1/(C_{R} + L_{R} + R_{2})) + 1/(C_{L}*s)))) - (-R_{1}*V_{in}(s)/(R_{1} +
1/(1/(1/(C_{T}*s + 1/(L_{R}*s + R_{2} + 1/(C_{R}*s))) + 1/(C_{L}*s)) +
1/(L_{L}*s))) + V_{in}(s))/(1/(C_{T}*s + 1/(C_{R} + L_{R} + R_{2})) +
1/(C_{L}*s))’
Is that usable or do I need to provide another means? Is that IPython doc
preferable (or the same in straight Python form)?
Thanks—
Greg
> On Jul 14, 2015, at 18:05 , Aaron Meurer <[email protected]> wrote:
>
> I think there is a bug. If you take the two expressions, subtract them, and
> call simplify(), you get a result that isn't 0. equals() also says they are
> different.
>
> simplify() returning False is also a bug.
>
> Can you open two issues for these things? Just put some minimal code to
> create the expressions in the issue (i.e., just print the expressions using
> str()).
>
> Aaron Meurer
>
> On Tue, Jul 14, 2015 at 12:51 PM, G.B. <[email protected]
> <mailto:[email protected]>> wrote:
> Hey Aaron—
>
> Maybe the best way to capture an example is an IPython notebook?
>
> Let me know if this doesn’t work properly…
>
> Cheers—
>
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> > On Jul 13, 2015, at 10:25 , Aaron Meurer <[email protected]
> > <mailto:[email protected]>> wrote:
> >
> > On Sun, Jul 12, 2015 at 7:46 PM, G B <[email protected]
> > <mailto:[email protected]>> wrote:
> >> What would case Eq.simplify() to return False? There isn't a lot of
> >> computation time before the result.
> >
> > Can you show an example of what is doing this?
> >
> >>
> >> Also why would using together() before substituting an expression lead to a
> >> numerically different result?
> >
> > How different? It's possible you are changing the numerical stability
> > of the expression. Or it's possible there is a bug in together.
> >
> > Aaron Meurer
> >
> >>
> >> I have a series of equations that I've been substituting in to each other
> >> building up a final symbolic result. My first pass at this gave a result
> >> that looks reasonable (though I haven't proven it correct) when I convert
> >> it
> >> to a numpy function after using
> >> Eq.subs(dictionary of values for symbols).simplify().n()
> >> and plot it.
> >>
> >> When I took the last symbolic equation to be substituted and use
> >> Eq.together() on it before substituting to get a simpler result, the
> >> Eq.subs().simplify() returns False. When I manipulate it differently to
> >> get
> >> it to successfully lambdify, the resulting plot is different (and appears
> >> wrong).
> >>
> >> Thanks--
> >>
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