With the right assumptions this will simplify:
>>> e=S('A + exp(B*log(C) + D) ')
>>> simplify(posify(e))
(_C**_B*exp(_D) + _A, {_A: A, _B: B, _C: C, _D: D})
>>> _[0].subs(_[1])
A + C**B*exp(D)
/c
On Saturday, July 18, 2015 at 6:12:37 AM UTC-5, Carsten Knoll wrote:
>
> Hi,
>
> due to various substitutions I have a bulky expression of the following
> structure
>
> A + exp(B*log(C) + D)
>
> I want sympy to simplify this to
>
> A + C**B*exp(D)
>
> I think it boils down to the simplification of
>
> exp(B*log(C))
>
>
> which I also can't perform:
>
> from sympy import exp, log, expand_power_exp
> from sympy.abc import B, C
>
> term = exp(B*log(C))
>
> print term.simplify()
> print term.expand()
> print expand_power_exp(term)
>
>
> # results
> exp(B*log(C))
> exp(B*log(C))
> exp(B*log(C))
>
> I think a possible way would be the following:
>
> exp(B*log(C) + D) = exp(B*log(C))*exp(D) = exp(log(C))**B*exp(D)
> = C**B*exp(D)
>
>
> But how can I tell sympy to "see" that?
>
> Carsten
>
>
>
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