Thank you very much, that did the trick.

Uwe

Am Donnerstag, 17. September 2015 00:07:14 UTC+2 schrieb Aaron Meurer:
>
> If you don't tell solve() that beta_2 is a parameter, it assumes that 
> it is a constant. It then returns no solutions because it solves eq1 
> and eq2 each for phi_2 and sees that they look different, because they 
> are only equal for certain values of beta_2 (at least, I'm fairly sure 
> this is what is happening). 
>
> You can get the solutions by telling solve that beta_2 is a parameter 
>
> In [14]: solve([eq1, eq2], [phi_2, beta_2]) 
> Out[14]: [(0.0, 1.0), (1.0, 0.0)] 
>
> Aaron Meurer 
>
> On Wed, Sep 16, 2015 at 6:12 AM, Uwe Fechner <[email protected] 
> <javascript:>> wrote: 
> > Hello, 
> > 
> > I try to calculate the tangent of a circle. This is a quite simple 
> system of 
> > equations (one is quadratic), 
> > but sympy fails (empty solution set). Any idea why? 
> > 
> > from __future__ import division 
> > from sympy import * 
> > from sympy.solvers import solve 
> > 
> > init_printing(use_latex = True) 
> > r, phi_0, phi_1, phi_2, beta_0, beta_1, beta_2= symbols('r phi_0, phi_1, 
> > phi_2, \ 
> >      beta_0, beta_1, beta_2') 
> > 
> > if True: 
> >     if True: 
> >         phi_0 = 0 
> >         beta_0 = 0 
> >         phi_1 = 1. 
> >         beta_1 = 1. 
> >         r=1. 
> >     eq1 = Eq((phi_2 - phi_1) * (phi_2 - phi_1) + (beta_2 - beta_1) * 
> (beta_2 
> > - beta_1) - r*r) 
> >     eq2 = Eq((phi_2 - phi_0) * (phi_2 - phi_1) + (beta_2 - beta_0) * 
> (beta_2 
> > - beta_1)) 
> >     result = solve([eq1, eq2], phi_2) 
> >     print result 
> > 
> > The result is an empty list. Any idea, how to fix this? 
> > Expected result: phi_2 = 1. 
> > 
> > Any hints appreciated! 
> > 
> > U. Fechner, TU Delft 
> > 
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