Hello.

Have you triez to expand 1nd then to factorize the formula ?
Le 1 janv. 2016 03:42, "Ken" <[email protected]> a écrit :

> I've just started learning Sympy. I wrote a few lines of code to perform a
> inverse laplace transform on a simple 2nd order transfunction:
>
> H(s) = 1 / ((s+p1) * (s+p2)).
>
> The result I got from Sympy is
>
> (e^(p1*t) - e^(p2*t))*e^-t*(p1+p2) / (p1 - p2)
>
> Is there a way to simplify this result to the one like in Maxima (e^-t*p1
> + e^-t*p2) / (p1-p2) ?
>
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