You can do it if you omit the assumptions. Otherwise, the only way is to
use Pow(2*pi, Rational(1, 2), evaluate=False).

Aaron Meurer

On Wed, Jan 20, 2016 at 4:31 PM, Jonathan Crall <[email protected]> wrote:

> I saw under http://docs.sympy.org/dev/tutorial/simplification.html#powsimp
>
> that it is impossible to combine radicals using powersimp:
>
> "This means that it will be impossible to undo this identity with
> powsimp(), because even if powsimp() were to put the bases together, they
> would be automatically split apart again."
>
> I was wondering if it was possible to do this any other way.
>
> For a toy example I have
>
>         import sympy
>         L = sympy.symbols('L', real=True, finite=True, positive=True)
>         sympy.sqrt(L) * sympy.sqrt(pi)
>
> and I would like to have it return sympy.sqrt(L * pi)
> Is there any way to do this?
>
> What I'd really like is if it combined these terms in this real example:
>
>         import simplify
>         import vtool as vt
>         import sympy
>         sigma, dist, L = sympy.symbols('sigma, distij, L', real=True,
> finite=True, positive=True)
>         kernel = (1 / sympy.sqrt(sigma ** 2 * 2 * sympy.pi)) *
> sympy.exp((-dist ** 2) / (2 * sigma ** 2))
>         phi = (1 / L) * kernel
>         logphi = sympy.simplify(sympy.log(phi))
>         logphi = sympy.logcombine(logphi)
>
> So I would get
> -distij**2/(2*sigma**2) - log(sqrt(2 * pi)*L*sigma)
>
> instead of
>
> -distij**2/(2*sigma**2) - log(sqrt(2)*sqrt(pi)*L*sigma)
>
>
>
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