Great, thanks!
On Tuesday, April 5, 2016 at 8:11:06 PM UTC+2, Aaron Meurer wrote:
>
> It works in that case too
>
> In [62]: u = Function('u')
>
> In [63]: u.__name__
> Out[63]: 'u'
>
> The important thing to note is that Function('u') creates *class*, not
> an object. Roughly speaking, Function('u') is syntatic sugar for
>
> class u(Function):
> pass
>
> (except it also sets the metaclass as UndefinedFunction)
>
> In other words, if you have a = u(x), then a.func is u.
>
> Aaron Meurer
>
>
> On Tue, Apr 5, 2016 at 2:04 PM, Nico <[email protected] <javascript:>>
> wrote:
> > I need to get the name (as a string) of certain given functions, and
> I've
> > typically done it like
> > ```
> > node.func.__name__
> > ```
> > That works, except for UndefinedFunctions. Is that an oversight? How to
> get
> > the 'hello' from u in
> > ```
> > u = sympy.Function('hello')
> > ```
> > ?
> >
> > Cheers,
> > Nico
> >
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