Yes, the number you pass to evalf is the digits of precision, like
expr.evalf(100) for 100 digits.

Aaron Meurer


On Friday, April 8, 2016, Amy Valhausen <[email protected]> wrote:

> Hi Aaron thanks so much for the reply will try this!  Is there any way to
> get more than 15 digits of accuracy?
>
> On Thursday, April 7, 2016 at 6:19:14 PM UTC-6, Amy Valhausen wrote:
>>
>> Fibonacci Reverse Calculation?
>>
>> Hi All!
>>
>> I was reading Dr Knotts entries about Binets formula on his fibonacci page
>>
>> http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/fibFormula.html
>>
>> I entered the formula into an Excel spreadsheet to see how this would
>> work ;
>>
>> Binet Formula
>> Fib(n) =  (1.6180339^n – (–0.6180339..)^n) / 2.236067977..
>>
>> Its fascinating to see how I can enter any number for (n) and see the
>> correct fibonacci number returned!
>>
>> I have a question though, I am a newbie computer programmer using
>> VB and Python and my math skills are average at best but I am very
>> interest and curious about math and especially fibonacci numbers!
>>
>> Say I wanted to reverse and change the process.
>>
>> I have a very large fibonacci number and I want to know what the
>> fibonacci number is at a specified position BEFORE it, how would
>> I compute this, what would the formula be?
>>
>> So for example I have the 301 st fibo number of ;
>>
>> 359579325206583560961765665172189099052367214309267232255589801
>>
>> And I want to be able to find what the fibonacci value would be (n)
>> numbers
>> BEFORE this... so I might want to know what the fibo value would be 50
>> numbers before or the 251st fibo number.  How would I do that?
>>
>>
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