Thank you Aaron, your response is very helpful.

Q.odd(d + 1) & Q.even(d) are deduced assumptions. It seems if I use the 
current method, Sympy can not get the conclusion "d is even" from "if (d+1) 
is odd" directly.
 

在 2017年5月29日星期一 UTC-6下午9:59:11,Aaron Meurer写道:

> None in this case means that SymPy doesn't know how determine the 
> fact. It looks like the sathandlers has an even/odd fact for Mul but 
> not for Add 
> https://github.com/sympy/sympy/blob/71eb404921a4596b9fe42a7a4a0ccfa7d63a62c0/sympy/assumptions/sathandlers.py#L339.
>  
>
> If I remember correctly, it's because the corresponding fact for Add 
> requires counting, and I wasn't sure how to do that efficiently 
> (without adding an exponential number of clauses for large Adds). 
>
> You can always tell SymPy the facts that it needs to know to deduce 
> things, in this case 
>
> >>> with assuming(Q.positive(c), Q.integer(c), Q.positive(d), 
> Q.integer(d), Q.odd(c*(d + 1)), Q.odd(d + 1) >> Q.even(d)): 
> ...     print(ask(Q.odd(d))) 
> False 
>
> here >> means "implies" (you could also use Implies(Q.odd(d + 1), 
> Q.even(d))). 
>
> Aaron Meurer 
>
>
> On Mon, May 29, 2017 at 9:45 PM, mike <[email protected] <javascript:>> 
> wrote: 
> > Hi, 
> > 
> > I am new to learn sympy. This is a very simple question but I do not 
> know 
> > how to deal with it. 
> > 
> > The question is: both c and d are positive integers, is c*d even if 
> c*(d+1) 
> > is odd. 
> > 
> > my code: 
> > 
> > from sympy import Symbol 
> > from sympy.assumptions import assuming, Q, ask 
> > c = Symbol('c') 
> > d = Symbol('d') 
> > with assuming(Q.positive(c), Q.integer(c), Q.positive(d), Q.integer(d)): 
> >     with assuming(Q.odd(c*(d +1))): 
> >         print(ask(Q.odd(c))) 
> >         print(ask(Q.odd((d+1)))) 
> > 
> > This code works. c is odd and (d+1) is odd, but how to evaluate d is odd 
> or 
> > even. 
> > I run the code 
> > ask(Q.odd(d)), 
> > but the result is "NONE" 
> > 
> > Ask for help. 
> > Thanks, 
> > 
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