I believe they are equal, according to SymPy's rule that (g'(t)).diff(g(t)) == 0:
f(g(t)).diff(t, g(t)) == (f'(g(t))*g'(t)).diff(g(t)) == f''(g(t))*g'(t) f(g(t)).diff(g(t), t) == f'(g(t)).diff(t) == f''(g(t))*g(t) You can also verify this with SymPy: >>> f(g(t)).diff(t).diff(g(t)) Derivative(f(g(t)), (g(t), 2))*Derivative(g(t), t) >>> f(g(t)).diff(g(t)).diff(t) Derivative(f(g(t)), (g(t), 2))*Derivative(g(t), t) Aaron Meurer On Tue, Aug 28, 2018 at 11:55 PM, Chris Smith <[email protected]> wrote: > SymPy allows derivative wrt non-Symbols. Under the current assumptions, > `g(t).diff(g(t),t) == g(t).diff(t, g(t)) == 0`. Can anyone give an example > where `f(g(t)).diff(t, g(t))` would not equal `f(g(t)).diff(g(t), t)`? > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. > Visit this group at https://groups.google.com/group/sympy. > To view this discussion on the web visit > https://groups.google.com/d/msgid/sympy/73c688ce-d447-4767-8ded-373346b822b7%40googlegroups.com. > For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CAKgW%3D6K68bpNidGjtPaRYPLA_SZ3OfYQfdubqq1R9_ygx2uu8A%40mail.gmail.com. For more options, visit https://groups.google.com/d/optout.
