Hey Jon,
I assume you want to do something like this:
>>> eq = x**2 - y
>>> solve(eq.subs({y:1}))
[-1, 1]
You can achieve this with `solveset` too:
>>> solveset(eq.subs({y:1}))
{-1, 1}
Primarily `solve` and `solveset` differs in the way they return output, the
former uses `list` while the latter uses `set`.
Below links, you might find helpful for getting along with `solveset`
https://docs.sympy.org/latest/modules/solvers/solveset.html
https://docs.sympy.org/latest/modules/sets.html
Cheers!
Yathartha
On Monday, January 28, 2019 at 2:17:52 PM UTC+5:30, Jon Durand wrote:
>
> Hello,
>
> I'm a fairly novice python user who had lightly brushed up against sympy a
> few years ago and understood a bit of the original solve.
> Lately I've been trying to write code for solving functions I use and
> would use a dictionary of symbol, value pairs and would solve things like
> this:
> solve( eq.subs(dictionary))
>
> I recently noticed the existence of solveset and the notice to use it over
> solve, so I am trying to convert my code to use solveset but I can't seem
> to find the information
> on how to substitute values into equations that are going into the solver.
> I imagine this is easy and I'm missing something simple but I've googled
> and read through a bunch of sympy doc pages and couldn't find the relevant
> part for solveset.
>
> Any help is greatly appreciated, thank you for your time.
>
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