Yes, you can do that with ImageSet: In [11]: ImageSet(Lambda(t, (t, t)), Interval(0, 1)) Out[11]: {(t, t) | t ∊ [0, 1]}
In [14]: ImageSet(Lambda(t, (t**2, t, 1-t)), Interval(0, 1)) Out[14]: ⎧⎛ 2 ⎞ ⎫ ⎨⎝t , t, 1 - t⎠ | t ∊ [0, 1]⎬ ⎩ ⎭ On Tue, 1 Oct 2019 at 22:58, EKW <etk...@gmail.com> wrote: > > For example if I wanted to represent the line segment from (0,0) to (1,1) > (f(t) = (t, t) for t in (0, 1))- can this be done with an image set? How? Or > a curve in 3d space (for example, f(t) = (t^2, t, 1 - t) for t in (0, 1)). > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to sympy+unsubscr...@googlegroups.com. > To view this discussion on the web visit > https://groups.google.com/d/msgid/sympy/8d96f817-802e-412e-948f-a3fc18361419%40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to sympy+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CAHVvXxSqefKtjfLa-NpVpSQ4NXvBPCKp81kanUkQSrdwU03Nzg%40mail.gmail.com.