There is still limited support for this, but you can use refine(expr, Q.positive(x - 2)). Actually, if all you want to do is simplify all roots in an expression you can use powdenest() and powsimp() with the force=True flag.
Aaron Meurer On Fri, Jan 17, 2020 at 12:26 PM Paul Royik <[email protected]> wrote: > > I know that variables can be made positive or negative. > > But how do I make assumption that x>2? > > If I have and expression like (x-2)^(1/3)+(x-5)^(1/3) (actually arbitrary > expressions), how to make assumptions that all expressions under roots are > positive, i.e. x-2>0, x-5>0? > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion on the web visit > https://groups.google.com/d/msgid/sympy/9edf1f7c-224d-4bf2-ba17-eea773465bb2%40googlegroups.com. -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/CAKgW%3D6K3keFtM%2BGjbMQd2e2-7pqM4Gv1X-oTht-TbZkNMvEH7g%40mail.gmail.com.
