I think that you should add a new method like **intersect**. I'm sure that 
intersections form a group, so it can be an another PermutationGroup, but 
union may not.

On Sunday, February 16, 2020 at 4:32:05 AM UTC+9, Mohit Gupta wrote:
>
> Hello everyone,
>
> I was thinking of Implementing *Permutation group triple product property* as 
> suggested by *S.Y. Lee* here (https://github.com/sympy/sympy/issues/18525 
> <https://www.google.com/url?q=https%3A%2F%2Fgithub.com%2Fsympy%2Fsympy%2Fissues%2F18525&sa=D&sntz=1&usg=AFQjCNHTJWoVceOSjRoYApYMIW4GRmq7Bg>
> ). 
> You can see more about it using these two links:
> 1.)https://en.wikipedia.org/wiki/Triple_product_property
> 2.)https://arxiv.org/pdf/1104.5097.pdf
>
> So there is one algorithm mentioned in here (2.)
> https://arxiv.org/pdf/1104.5097.pdf Which is given below.
>
> Here *S, T, U *are *subgroups.*
>
> So I am expriencing some problem in implementation of this algorithm.
>
>    - As we can see intersection is used here and till now sympy does not 
>    contain any function for *intersection of two groups*.
>    - We can also see that here we are interested in finding whether the 
>    intersection of two subgroups is *trivial* or not so maybe se can 
>    avoid calculating intersection for of two groups.
>    - I was also thinking of using property "T*wo Normal Subgroups 
>    Intersecting Trivially Commute Each Other*" (
>    
> https://yutsumura.com/two-normal-subgroups-intersecting-trivially-commute-each-other/)
>  
>    but this will work only for *Normal groups*.
>
> Can we have discussion that what should be the best approach here?
>
> def test(S, T, U):
>     if( T ∩ U = 1 ) then
>         if( S ∩ T · U = 1 ) then
>             return true;
>     fi; fi;
>     return false;
>
>

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