Hi Javier,
I'm not sure exactly the problem with the example you showed. I think
it's a bug somewhere.
It is usually better not to use floats in sympy. With exact rational
numbers your example works for me:
In [17]: inverse_laplace_transform(S.Half/(S.Half*s+1)*1/s, s, t)
Out[17]:
-2⋅t
θ(t) ℯ ⋅θ(t)
──── - ─────────
2 2
Oscar
On Wed, 6 May 2020 at 18:36, Javier Arantegui
<[email protected]> wrote:
>
> Hello!
>
> I'm using Sympy 1.5.1 and Python is 3.7.7. Both installed using Anaconda.
>
> I have tried to do an inverse Laplace transform and I got an error:
>
> inverse_laplace_transform(0.5/(.5*s+1)*1/s, s, t)
>
> The error message is quite long, tell me if you need it.
>
> I spent 10 minutes in front of my students trying to think what was wrong...
>
> Finally, I was able to solve it with an easy change:
>
> inverse_laplace_transform(0.5*2/(2*(.5*s+1))*1/s, s, t)
>
>
> Best regards,
>
> Javier
>
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