The output from solve for algebraic equations is not usable without testing
output because of the variable types of output.
CASE 1: If no variables are given we get the following from the input:
* univariate equation -> list of values
>>> solve(x**2 - 4)
[-2, 2]
* multivariate equation -> list of one or more dictionaries
>>> solve(x**2 - y)
[{y: x**2}]
CASE 2: If variable(s) are given we get
* tuples of solutions
>>> solve([x**2-y],x)
[(-sqrt(y),), (sqrt(y),)]
* dictionary for single solution
>>> solve([x-y],x)
{x: y}
Although the dict=True or set=True will give a standard output, can we at
least unify the case for when variables are given so we always get a list
of one or more dictionaries? So the above would be `[{x: -sqrt(y)}, {x:
sqrt(y)}]` and `[{x: y}]`, respectively. This would then make `solve`
always give a list of a) values for a univariate expression, b) a list of
one or more dictionaries for every other case. (Case (a) will give a list
of dictionaries if `dict=True`.)
/c
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