Thanks to Python’s function definition facilities, you can collect your
arguments as a list and use them as such in your function definition :
>>> from sympy import symbols
>>> X=symbols("x:5") ; X
(x0, x1, x2, x3, x4)
>>> def foo(*u): return "I got %d arguments."%len(u)
...
>>> foo(X) # Call foo with the single argument X
'I got 1 arguments.'
>>> foo(*X) # Call fo with the LIST of arguments (x0,...,x4)
'I got 5 arguments.'
You can also have fixed arguments before the list argument :
>>> def bar(u, *v): return "u=%s, v=%s"%(u, v)
...
>>> bar(*X)
'u=x0, v=(x1, x2, x3, x4)'
HTH,
Le vendredi 20 mai 2022 à 07:35:57 UTC+2, [email protected] a écrit :
> Hi,
> I am a new hand in sympy. I have some questions when I using it. Could you
> please help me?
>
> When I use "x = symbols('x:(n+1)')" to claim (n+1) variables, after the
> calculations, I can get the results represented by x0, x1, x2,...xn, i.e.,
> f(x0, x1, ..., xn), where n can change from time to time.
> Now, I have several sets of input data, and I want to know the results of
> the calculated function, i.e., f(input), where each set of input data has n
> elements.
> I am trying to convert the f(x0, x1, ..., xn) by using lambdify. For
> example, I can only do obj = lambdify(x, f(x[0], x[1], x[2], ..., x[n]))
> rather than lambdify(x, f(x0, x1, ..., xn)).
> How can I use the previous calculated f(x0, x1, ..., xn) in lambdify
> directly?
>
> In addition, when I calculate the result, I can only do obj(input[0],
> input[1], ..., input[n]), can I read the input array directly, i.e.,
> obj(input)?
>
> Thanks for your time.
>
> Best,
> Junjie
>
>
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