Hello! I'm trying to get my head wrapped around how to use SolveSet (and
whether I should be using solve or some other method instead), and I ran
into the following problem.
I have two sets:
Solution_Set=solveset(Eq(y,x+x/2),y,S.Reals)
Solution_Set2=solveset(Eq(y,1.5*x),y,S.Reals)
Now I want to compare these sets and I was expecting the sets to be
equivalent. I know they're not "equal" (different forms), but I was
expecting them to be the same set.
I don't see how I can use simplify here, so I tried the following:
Contains(Solution_Set,Solution_Set2)
False
Contains(Solution_Set2,Solution_Set)
False
Intersection(Solution_Set,Solution_Set2)
[25]: R∩{1.5x}
Solution_Set2-Solution_Set
[37]: ∅
Solution_Set-Solution_Set2
[38]: (R∩{3x2})∖(R∩{1.5x})
It would appear that solveset(Eq(y,x+x/2),y,S.Reals) is a superset of
solveset(Eq(y,1.5*x),y,S.Reals) solveset(Eq(y,1.5*x),y,S.Reals), but
Contains didn't work!
Is there another way that I should be doing this, or a better way to do
this comparison? Note that I can't just simplify 3*x/2-1.5*x for a variety
of reasons - the application might not make it that simple (I've simplified
my issue to this test case).
Thanks!
Kevin
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