This code:
import sympy as sm
x = sm.symbols('x')
f = sm.integrate(sm.sqrt(1-x**2), (x, 0, 1))
print('f=', f)
gives:
f = pi /4
From: [email protected] <[email protected]> On Behalf Of Ajith Kumar
Sent: Dienstag, 23. April 2024 10:43
To: sympy <[email protected]>
Subject: [sympy] Area of circle by integration
from sympy import *
x,y = symbols('x y')
y = sqrt(1 - x**2)
integrate(y,x ,(x, 0, 1)).evalf()
result is
0.452064830064115
I expected value of Pi/4, by integrating a quarter of a circle with unit
radius. Can anyone explain the reason, I am new to Simpy.
Regards
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