What is x^(3/5)? On Wednesday, December 11, 2024 at 11:36:20 PM UTC+2 [email protected] wrote:
> If I put it as (x^2)^(1/5) it works fine. > > > > *From:* [email protected] <[email protected]> *On Behalf Of *Paul > Royik > *Sent:* Wednesday, December 11, 2024 8:15 PM > *To:* sympy <[email protected]> > *Subject:* [sympy] Real-valued root > > > > I try to use the bridge between sympy and numpy, namely, the lambdify > function. > > > > It looks ok, but there is an issue when I try to calculate the values of > x^(2/5) on the interval [-5,5]. > > > > Of course, for negative x, the value is nan, because, I guess, the root is > not real-valued. > > How to make it real-valued? > > > > Thank you. > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion visit > https://groups.google.com/d/msgid/sympy/02b3834f-d2ba-4767-a28e-4b6ae1355906n%40googlegroups.com > > <https://groups.google.com/d/msgid/sympy/02b3834f-d2ba-4767-a28e-4b6ae1355906n%40googlegroups.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion visit https://groups.google.com/d/msgid/sympy/f074e2b9-28a4-4ce0-8208-996d67a1aac2n%40googlegroups.com.
