Thank you, Peter but there is not quite what I was looking for.

Technically your result simply proves that the square root of the square of a 
real number x is the absolute value of x (\sqrt{x^2} = |x| for x \in reals).  
Or in your terms:

    test = |sin(INC)|/\sqrt{sin(INC)^2}  for INC real

is always, identically, equal to 1.

For my case, sin(INC)/|sin(INC)| is what I am looking at (i.e., the numerator 
has no absolute value), and it is equal to 1 for my assumptions but how can 
sympy know that without knowing that I've restricted INC to the range [0,\pi]?  
If, for example,  INC were in the range [\pi,2\pi] then sin(INC)/|sin(INC)| = 
-1.

If there is a way to say something like:

    INC = sm.symbols(‘INC’, real=True,range=[0,pi])

then I say that the result is proved.  But I can't anything like this in the 
documentation (perhaps I simply don't know where to look).

Conrad















________________________________
From: [email protected] <[email protected]> on behalf of 
[email protected] <[email protected]>
Sent: Tuesday, January 21, 2025 9:39 AM
To: [email protected] <[email protected]>
Subject: RE: [sympy] trigsimp, assumptions, and vector magnitudes


I guess sympy does not know that INC is real and sin(INC) > 0.

I just tried:

INC = sm.symbols(‘INC’, real=True)

test = sympy.Abs(sympy.sin(INC)) / sympy.sqrt(sympy.sin**2(INC))



test = 1 was the result, as expected



From: 'Conrad Schiff' via sympy <[email protected]>
Sent: Tuesday, January 21, 2025 2:57 PM
To: [email protected]
Subject: [sympy] trigsimp, assumptions, and vector magnitudes



I am writing a textbook on orbital mechanics and I would like to use sympy for 
certain calculations (e.g., deriving expressions for certain vectors in terms 
of Keplerian orbital elements) so that the readers realize the power of sympy.  
I have a specific problem I am hoping this group could help me with as I am 
also fairly new to sympy.  Here is a minimum working example:



********************************

from sympy import *



A, INC = symbols('A INC')

zxh = Matrix([[-sin(A)*sin(INC)], [cos(A)*sin(INC)], [0]])

********************************



At this point, I want to unitize 'zxh' so that the sin(INC) divides out.  This 
is a legitimate step since the range of INC is restricted to 0 to \pi and the 
sin(INC) is always non-negative (I am ignoring the singularities on the 
boundaries of 0 and \pi).  I tried the following but I get the errors below.  
Some help in coaxing sympy to do what I know can be done would be appreciated.



********************************

mag2_zxh = trigsimp(zxh.dot(zxh))

    -> gives sin**2(INC)



mag_zxh = sqrt(mag2_zxh)

   -> gives  sqrt(sin(INC)**2)



zxh/mag_zxh

   -> gives Matrix([[-sin(A)*sin(INC)/sqrt(sin(INC)**2)], 
[sin(INC)*cos(A)/sqrt(sin(INC)**2)], [0]])



********************************

How can I coax sympy into recognizing that "sin(INC)/sqrt(sin(INC)**2) = 1"?



Thanks for any help,

Conrad Schiff, PhD

Professor of Physics

Capitol Technology University

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