If you replace -2/5 with -0.4, WolframAlpha says that the series 
diverges: 
https://www.wolframalpha.com/input?i=sum%28binomial%28-0.4%2C+n%29%2C+%28n%2C+1%2C+inf%29%29

On Wednesday, September 10, 2025 at 2:48:04 PM UTC+3 Oscar wrote:

> I don't think wolframalpha says it is divergent:
>
>
> https://www.wolframalpha.com/input?i=sum%28binomial%28-2%2F5%2C+n%29%2C+%28n%2C+1%2C+inf%29%29
>
> It does not compute the sum in closed form but gives a formula for the
> partial sums as
>
> 2^(-2/5)-1 + f(k)
>
> where f(k) is something that goes to zero for large k.
>
> SymPy gives the same partial sum formula in terms of 2F1 (hyper)
> although it looks a little different with gamma functions:
>
> In [29]: print(summation(binomial(S(-2)/5, n), (n, 1, k)))
> (5/2 - 5*2**(3/5)/4)*gamma(3/5)/gamma(-2/5) - gamma(3/5)*hyper((1, k +
> 7/5), (k + 2,), -1)/(gamma(-k - 2/5)*gamma(k + 2))
>
> I think SymPy and WolframAlpha are in agreement but just WA does not
> compute a closed form for this particular sum whereas SymPy does get
> the closed form but SymPy does not simplify the gamma functions as
> nicely as WA does.
>
> I think simplify here could be improved:
>
> In [33]: e = summation(binomial(S(-2)/5, n), (n, 1, oo))
>
> In [34]: print(e)
> (5/2 - 5*2**(3/5)/4)*gamma(3/5)/gamma(-2/5)
>
> In [35]: e.evalf()
> Out[35]: -0.242141716744801
>
> In [36]: 2**(-2/5)-1
> Out[36]: -0.242141716744801
>
> In [37]: print(simplify(e))
> 5*(2 - 2**(3/5))*gamma(3/5)/(4*gamma(-2/5))
>
> Maybe gammasimp could handle this better somehow.
>
> --
> Oscar
>
> On Wed, 10 Sept 2025 at 12:19, Paul Royik <distan...@gmail.com> wrote:
> >
> > sum of binomial(-2/5, n), n=1..infinity
> >
> > SymPy says that the answer is 2^(-2/5)-1.
> > WolframAlpha says that the series is divergent.
> >
> > What answer is correct?
> >
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