>  part.decode
>  htmlviewer.loadfromstring(part.PartBody.Text);

What is it? You must call: 

part.DecodePart;
htmlviewer.loadfromStream(part.DecodedLines);

When htmlviewer ask you for some image, you must find MIME part with 
data, decode it by DecodePart, and then read binary image data from 
DecodedLines stream.



-- 
Lukas Gebauer.

http://synapse.ararat.cz/ - Ararat Synapse - TCP/IP Lib.
http://geoget.ararat.cz/ - Geocaching solution


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