В сообщении от Tuesday 29 July 2008 14:25:55 Aleksey E. Birukov написал(а):
> Как вывести определенное поле в awk понятно {print($1)}. А вот как
> вывести сам текст-разделитель,
echo "aaa_bbb_ccc" | gawk 'FS = "_" { print FS }'
из man gawk
FS variable as the field separator. If FS is a single character, fields
are separated by that character. If FS is the null string, then each
individual character becomes a separate field. Otherwise, FS is expected to
be a full regular expression.
Оно?
--
С уважением
Сергей Шилов.
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