Well, you could try <%= request.getRequestURI() %> or <%= request.getRequestURL() %>
I was trying to get similar information sometime back, and i tried the above, but it didn't quite work for me - not sure if it was the particular case in which i was trying or what.. but again, according to the docs, it should give you want you want.. :) I'll be interested to find out if it works for you. > > Did you try: > > > > <%= request.getContextPath() %> > > > > According to the javadocs for HttpServletRequest, that > should return what > > you're looking for. > > Thank you. Quite why I didnt spot this before, I dont know. > I'm sure I've > looked for this on a number of occasions! :) > > I assume there isn't anything to build a complete url for the > context, ie if > you're running tomcat on 8080, and you want to build a > https:// url like > > https://thehost:8080/ request.getContextPath() ?:) > > > > > > Ok ok, i know this isn't tag related. But it's so quick that > > > I think someone > > > might know ;-) > > > > > > If I have a webapp installed under /wiggle, can I get at the > > > path "/wiggle" > > > from my webapp? So I can put: > > > > > > <a href="<%= application.getSomethingThatReturnsPath() > > > %>somepage.jsp"> -- To unsubscribe, e-mail: <mailto:[EMAIL PROTECTED]> For additional commands, e-mail: <mailto:[EMAIL PROTECTED]>
