I think your question will be resolved by a simple XPath.
If you transform your xml by XSLT, you can do it with the following
stylesheet:
------------------------------------------------------------------
<xsl:transform version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:apply-templates select="//created"/>
</xsl:template>
<xsl:template match="created">
<xsl:choose>
<xsl:when test="number(.) > 20011231235959">
<!-- convert "yyyyMMddHHmmss" to "dd.MM.yyyy HH:mm:ss" -->
<xsl:value-of select="concat( substring( . , 7 , 2) ,
'.' ,
substring( . , 5 , 2) ,
'.' ,
substring( . , 1 , 4) ,
' ' ,
substring( . , 9 , 2) ,
':' ,
substring( . , 11 , 2) ,
':' ,
substring( . , 13 , 2) )"/>
</xsl:when>
<xsl:otherwise>
<xsl:message terminate="yes"
>[EMAIL PROTECTED]'created'] : invalid content of
<created></xsl:message>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:transform>
--------------------------------------------------------------
With this xsl, you will get "03.10.2003 17:38:34" from
"<created>20031003173834</created>".
You also achieve the similar transformation by <x:out select="...xpath
expression..."/>
where the xpath expression will be the equivalent one to the value of
select attribute of the following:
<xsl:value-of select="concat( substring( . , 7 , 2) ,
'.' ,
substring( . , 5 , 2) ,
'.' ,
substring( . , 1 , 4) ,
' ' ,
substring( . , 9 , 2) ,
':' ,
substring( . , 11 , 2) ,
':' ,
substring( . , 13 , 2) )"/>
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