On Tue, Jul 9, 2013 at 9:53 AM, Iraklis . <[email protected]> wrote: > That would destroy any dedup service if different random bytes are appended. > Even if the same number of random bytes are appended for equivalent > encryption keys. Or i am missing sth?
Hello, Iraklis! Good to hear from you. Let's make all pad bytes be "0" before encryption. They will be encrypted along with the file bytes. Therefore, as long as the same number of padding bytes are appended whenever the encryption key is the same, then the dedup (convergent encryption) property is preserved. Right? Regards, Zooko _______________________________________________ tahoe-dev mailing list [email protected] https://tahoe-lafs.org/cgi-bin/mailman/listinfo/tahoe-dev
