If your professor was referring to PHP, it's possible he could have been
referring to objects, not arrays. Objects are copied by reference, so if
you do this:
$Item = new Item;
$Item2 = $Item;
$Item2->setProductId('12');
print $Item->getProductId();
Your output will be '12'. If you want to copy an object in PHP 5 you'll
need to use 'clone.'
Aaron Fischer wrote:
Indeed it does. Sorry! I was led to believe (by my cs professor) that
the default behavior when copying an array is that the copied array is
not a new instance but is tied by pointers to the old array, so changes
to one would change both of them. Other people in the class are using
python and java, and apparently that is the case for them as they need
to use separate functions to make sure the copy created is not tied to
the old array.
Down near the bottom of the php.net page on arrays, right before the
user comments:
You should be aware that array assignment always involves value copying.
It also means that the internal array pointer used by current() and
similar functions is reset. You need to use the reference operator to
copy an array by reference.
http://us2.php.net/manual/en/language.types.array.php
-Aaron
On Feb 25, 2007, at 5:39 PM, Daniel Convissor wrote:
Aaron:
On Sun, Feb 25, 2007 at 03:47:45PM -0500, Aaron Fischer wrote:
I need to copy an array by value, not by reference. Is there a best
way to do this? Right now I found serialize/unserialize which seems
to do the trick.
What ARE you talking about? Copying by value is the default behavior in
PHP.
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