Hi everybody,

Thanks for the information, unfortunately for me there are no arrays being used. The names used are solely the names of each individual column/field in the table. I have already tried all the suggestions to no avail. That is why I hardcoded a version of my insert-data-into-table and once I knew it worked I substituted all the hardcoded fields with $_POST in place of the hardcoding, I then cut and pasted in each field the corresponding hardcoded value and just before writing the record. I echoed the record values and all appears to be well. Then via the MySQL Monitor I check to see if the record had been written and found that nothing has happened. Please forgive me if I appear to be ungrateful, which is not the case I am just frustrated. Especially after proving that one version of my insert-data-into-table (hardcoded) worked and a version of my insert-data-into-table works with a 4 column table (a different table) and will not work with a version using as input data the values of the hardcoded version. I knows the fault lays with me but I cannot see it.

Paul
----- Original Message ----- From: "csnyder" <[EMAIL PROTECTED]>
To: "NYPHP Talk" <talk@lists.nyphp.org>
Sent: Monday, July 23, 2007 7:04 PM
Subject: Re: [nyphp-talk] inserting data into MySQL table.


On 7/23/07, Jon Baer <[EMAIL PROTECTED]> wrote:
Id guess that one of your data types (or more) is still not valid for
the type declared but ~not sure if you know this~ but you can add
column names before your query ...

INSERT INTO my_table (col1_name, col2_name) VALUES (col1_value,
col2_value) // Try a few values up until you error out


I find it even less confusing to use the SET variant that makes
INSERTs look like UPDATEs:

INSERT INTO my_table SET col1_name=col1_value, col2_name=col2_value;


--
Chris Snyder
http://chxo.com/
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