Could you provide the HTML from the initial setup (the one that was broken)?
I'm curious about what was output to the browser (since that's what dictates
where the form is sent anyway)
Thanks
On 7/24/07, Anthony Wlodarski <[EMAIL PROTECTED]> wrote:
Donald,
Thanks for the recommendation, I tried it and it did not work. I even
looked up one level to the function that calls this function and I
couldn't
trace back and incorrect code. I moved the code out of the function and
put
it in its own php file:
<?php
echo "<form action='./edit.php' method='post'>\n";
echo "<input type='hidden' name='id'
value='".$row['id']."'>\n";
echo "<input type='hidden' name='database'
value='candidate'>\n";
echo "<input type='submit' name='edit' value='Edit'>\n";
echo "<form>\n";
?>
Results: It pointed to edit.php. This is weird and mind blowing as well.
Anthony Wlodarski
Technical Recruiter
Shulman Fleming & Partners
646-285-0500 x230
[EMAIL PROTECTED]
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On
Behalf Of Donald Organ
Sent: Tuesday, July 24, 2007 11:15 AM
To: NYPHP Talk
Subject: Re: [nyphp-talk] Having problems with PHP or maybe something
bigger...
try turning
echo "<form action='./edit.php' method='post'>\n";
into
echo "<form action='/edit.php' method='post'>\n";
On Tue, 2007-07-24 at 11:08 -0400, Anthony Wlodarski wrote:
> Hello all,
>
> I am currently contracted by my boss to create a candide/company
tracking
system in PHP/MySQL and have hit a little snag.
>
> Here is the code:
>
> function displayCandidates($managerid)
> {
> $sqlcandidates = "SELECT * FROM `candidate` WHERE `managerid` =
".$managerid."";
> $resultcandidates = mysql_query($sqlcandidates) or die('Error, get
candidates query failed');
>
> while($row = mysql_fetch_array($resultcandidates, MYSQL_ASSOC))
> {
> echo "<tr style='border: solid 2px black;
background-color:
".$row['color']."'>\n";
> echo "<td style='border: solid 2px black; width:
100px;'></td>\n";
> echo "<td style='border: solid 2px black; width:
300px;'></td>\n";
> echo "<td style='border: solid 2px black; width:
300px;'>".$row['name']."</td>\n";
> echo "<td style='border: solid 2px black; width:
100px;'>".$row['status']."</td>\n";
> // add a edit button
> echo "<td style='border: solid 2px black; width: 100px;
text-align: center;'>\n";
> echo "<form action='./edit.php' method='post'>\n";
> echo "<input type='hidden' name='id'
value='".$row['id']."'>\n";
> echo "<input type='hidden' name='database'
value='candidate'>\n";
> echo "<input type='submit' name='edit' value='Edit'>\n";
> echo "<form>\n";
> echo "</td>\n";
> echo "</tr>\n";
> }
> }
>
> Now that code would create a button at the end of the table row that
should call the php file "edit.php" however when I go to the webpage the
button links to "names.php" which is the name of the file that contains
this
code. I do have references to $_SERVER['PHP_SELF'] in the code in other
places to call the script itself if certain buttons are pressed but I
don't
see how that could have interfered. It is blowing my mind because I
thought
it would be a simple thing to fix but I can't figure it out. I even moved
the form echo statements to a test file on the server and it does not do
this at all.
> -Anthony W.
> Technical Recruiter
> Shulman Fleming & Partners
> [EMAIL PROTECTED]
> 646 285 0500 x230
>
>
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_______________________________________________
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http://www.nyphpcon.com
Show Your Participation in New York PHP
http://www.nyphp.org/show_participation.php
_______________________________________________
New York PHP Community Talk Mailing List
http://lists.nyphp.org/mailman/listinfo/talk
NYPHPCon 2006 Presentations Online
http://www.nyphpcon.com
Show Your Participation in New York PHP
http://www.nyphp.org/show_participation.php
_______________________________________________
New York PHP Community Talk Mailing List
http://lists.nyphp.org/mailman/listinfo/talk
NYPHPCon 2006 Presentations Online
http://www.nyphpcon.com
Show Your Participation in New York PHP
http://www.nyphp.org/show_participation.php
