No. $i++ returns the value of $i, then increments it.
On Thu, Jul 3, 2008 at 12:45 PM, Michael Southwell <
[EMAIL PROTECTED]> wrote:
> John Campbell wrote:
>
>> $p = explode('|',$y);
>> for($i=0,$c = count($p);$i<$c;) {
>> echo $p[$i++],' ', $p[$i++], "<br>\n";
>> }
>>
>
> I believe this will miss the first element of $p; you need instead:
>
> for ( $i = -1, $c = count( $p ); $i < $c; ) {
>
>
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> Michael Southwell
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