Hi all. I have a question regarding the below syntax
$result = isset($a['c']) ? $a['c'] : NULL;
This is testing two conditions, first if $a['c'] is set, and then, if $a
['c'] is NULL...correct?
What would $result be if $a['c'] is set but is not NULL? The same as
if $a['c'] was not set? or...?
I've seen similar syntax before, in some code Tedd & I were working
with a couple of months back...and just want to make sure I fully
understand what is actually happening with it.
Thanks.
-- Kristina
> On Sun, Aug 17, 2008 at 4:49 PM, Michael B Allen <[EMAIL PROTECTED]>
wrote:
> > Is it ok to access non-existent array elements?
> >
> > Will accessing an array element using a key that does not exist
always
> > return NULL?
>
> it depends on how you have warnings configured. you might be getting
> them in your log, for example... i believe the result of accessing a
> non-existent array element is undefined.
>
> if i were you, i'd prob'ly ask if it exists first:
>
> <?php
>
> $result = isset($a['c']) ? $a['c'] : NULL;
>
> /** OR **/
>
> $result = array_key_exists('c', $a) ? $a['c'] : NULL;
>
> ?>
>
> see:
>
> http://us2.php.net/function.isset
> http://us2.php.net/function.array-key-exists
>
>
> justin
> --
> http://justinhileman.com
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