On Jan 4, 2011, at 4:50 PM, Dan Cech wrote:
> Rob,
> 
> This is demonstrating 2 special cases which will work properly:
> 
> 1. no rows for a parent in one of the child tables
> 2. 1 row for a parent in both child tables
> 
> If you run your child inserts again to create more rows you'll end up with a 
> count of 4 instead of 2 in the 3rd row.

Ah yes... there it is.  I knew there was a reason I don't remember doing two 
counts in one query before.  Thanks for the free lesson!  ;)


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