Stefan de Konink schrieb: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA512 > > Op 22-03-10 04:20, Bernhard zwischenbrugger schreef: > >> Hint: >> >> At first you maybe think >> centerLat = (minlat + matlat)/2; >> centerLng = (minlng + matlng)/2; >> could be the solution. >> >> But that does not give the correct result. >> The center must be the center in screen coordinates. >> > > I think your problem is more fundamental; because min and max are not > going to work ;) lefttop, righttop, leftbottom, right bottom are. > Good Point you are right on that. I have 2 Points in WGS84:
Southeast (example 0,0) Northwest (example 90, 180) A Mercator projection will result in a y value of infinite for this example. Not easy ... Bernhard > > Isn't it the idea: > > (max - min) / 2? > > You propose it the opposite. > > Its late, but I hope you have something for what I have attached. > > > Stefan > -----BEGIN PGP SIGNATURE----- > Version: GnuPG v2.0.14 (GNU/Linux) > Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ > > iEYEAREKAAYFAkum5mcACgkQYH1+F2Rqwn0WQQCdHP9rKyyaU7W9RddU8L9QV+ej > 2j0AnRrVBjbeRwZDtGhn8d1Wk14RZZ63 > =DdMd > -----END PGP SIGNATURE----- > > > ------------------------------------------------------------------------ > _______________________________________________ talk mailing list [email protected] http://lists.openstreetmap.org/listinfo/talk
