I hadn't thought of that.
Thanks!

Denis

-----Original Message-----
From: Paul Ferraro [mailto:[EMAIL PROTECTED] 
Sent: sexta-feira, 1 de abril de 2005 01:05
To: Tapestry users
Subject: Re: Unique Validator in Foreach loop

Off the top of my head, try something like this:

public class UniqueValidator implements IValidator
{
    private Set valueSet = new HashSet();

    public toObject(IFormComponent field, String input) throws 
ValidatorException
    {
       // Preliminary validation

       // Validate uniqueness
       if (valueSet.contains(input))
       {
          // Duplicate field!
          throw new ValidatorException(field.getDisplayName() + " must 
be unique.");
       }

       valueSet.add(input);
    }

// ...
}

Then make sure that your UniqueValidator bean is request scoped.

Paul

Denis Souza wrote:

>Hi,
>
> 
>
>I have a Foreach loop in which I want to validate the fields inside it. For
>any regular required or minimum-length validation that's fine, but I'm
>trying to build a validator that checks if each field is unique. For
>example, let's say the only field I have inside the foreach loop is a field
>for a name. Let's say this loop iterates 5 times so that there would be 5
>text fields rendered. I would like each of these "names" to be unique.
>
> 
>
>What I have done so far is, I created a validator called UniqueValidator
and
>I'm passing it the same list of objects to perform the validation that I
use
>in the foreach loop. This implementation causes two problems:
>
> 
>
>1) Tapestry is updating the list of objects with the submitted values only
>after the validations run, so I'm actually checking for uniqueness in a
>deprecated list. I have to be able to see the values that were just
>submitted in case the user changes more than one value.
>
> 
>
>2) I can't tell where in the object list is the field that is being
>validated, so I can't skip the item on the list that is being checked and I
>end up returning validation errors even if a name is entered only once in
>the list. I can work around this by checking if there is more than one
>object in the list that is the same as the input, but I don't think it's
>such an elegant solution.
>
> 
>
>Any ideas?
>
> 
>
>Thanks,
>
>Denis
>
> 
>
>
>  
>


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