Hey, How does '/bin/sh -c' with multiple args actually work?
The manual page says sh -c command_string [command_name [argument ...]] is valid, and should behave as such: "Read commands from the command_string operand instead of, or in addition to, from the standard input. Special parameter 0 will be set from the command_name operand if given, and the positional parameters (1, 2, etc.) set from the remaining argument operands, if any." So I would expect sh -c /bin/sleep whatever 30 to lead to "/bin/sleep 30" being invoked with an argv0 set to "whatever". However: $ sh -c /bin/sleep whatever 30 usage: sleep seconds Now I know that I can do $ sh -c "/bin/sleep 30" but the manual page suggests I should be able to set argv0 of the command as described above, but I don't see a way of actually doing that. What am I missing? -Jan
