Assuming the input is only having As and Bs, this would do the trick.
bool isproper(char * str)
{
int counter=0;
while(*str) counter+= ( (*(str++) ^ 'B' -1 );
return ! counter;
}
Melchi
On 7/12/05, Jayarajaganesh <[EMAIL PROTECTED]> wrote:
> Hi,
> i need a C or C++ program for a language that has
> words in which the number of Bs is twice than the
> number of As. I need a prog without much of counters
> and less no of conditions like if
> ganesh
>
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