awk(1) rshift/lshift on the borders of int

[Martin Pelikan]

I can't say anything more than 'this solved my problem', which was 

$ echo | awk '{ printf "%u\n", rshift(int("0xdeffffff"), 24) }' | bc -e
'obase=16' 
FFFFFF80

vs.

$ echo | awk '{ printf "%u\n", rshift(int("0xdeffffff"), 24) }' | bc -e
'obase=16'    
DE

I hope it starts a discussion (at least), but I don't really know what
the correct way is to these problems.

--
Martin Pelikan


Index: run.c
===================================================================
RCS file: /cvs/src/usr.bin/awk/run.c,v
retrieving revision 1.33
diff -u -p -r1.33 run.c
--- run.c       28 Sep 2011 19:27:18 -0000      1.33
+++ run.c       17 Jan 2012 15:01:32 -0000
@@ -1562,7 +1562,7 @@ Cell *bltin(Node **a, int n)      /* builtin 
                        break;
                }
                y = execute(a[1]->nnext);
-               u = ((int)getfval(x)) << ((int)getfval(y));
+               u = ((long long)getfval(x)) << ((long long)getfval(y));
                tempfree(y);
                nextarg = nextarg->nnext;
                break;
@@ -1573,7 +1573,7 @@ Cell *bltin(Node **a, int n)      /* builtin 
                        break;
                }
                y = execute(a[1]->nnext);
-               u = ((int)getfval(x)) >> ((int)getfval(y));
+               u = ((long long)getfval(x)) >> ((long long)getfval(y));
                tempfree(y);
                nextarg = nextarg->nnext;
                break;