Jonathan Mangin wrote:
Is it possible to sort a multi-valued hash?
In psuedo-code (all cols are text):
$menu{id} = [concat(col2,col3), col2, col3];
I hoped it would default to sorting on value.0, but output
appears random.
[% FOREACH item IN menu.sort %]
[% IF menu.$item.1 == rows.0.1 %]
<option value="[% item %]" selected>[% menu.$item.0 %]
[% ELSE %]
<option value="[% item %]">[% menu.$item.0 %]
[% END %]
[% END %]
Two (or more) of these constructs in the template sort in
the same order. It must not be random but I can't see the
pattern. Is there anything else I can do to get a sort on
value.0?
I think you'll need to create your own hash virtual method, or use a different
structure.
Something like this might work:
menu = [
{id => 'xxx', column1 => concat(col2,col3), columns => [col2, col3]},
{id => 'xxx', column1 => concat(col2,col3), columns => [col2, col3]},
{id => 'xxx', column1 => concat(col2,col3), columns => [col2, col3]},
]
Then [% FOREACH item IN menu.sort('column1') %]
Here's an example vmethod that works on your hash above. (Well maybe. I didn't
test or think about it much):
$Template::Stash::HASH_OPS->{ sort_array } = sub {
my ($hash, $index) = @_;
return sort {$hash->{$a}->[$index] cmp $hash->{$b}->[$index] } keys %$hash;
};
Usage: [% FOREACH item IN menu.sort_array(0) %]
Of course you might want to make it a bit more robust than that, or change it
to suit your needs.
-- Josh
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