Hi Madhavan, Madhavan Venkataraman wrote: > The stock kernel does not have a problem as the timeout > handler does not acquire any mutex. It only does setrun(). > But the stock kernel has another race condition where the > timeout can fire even before the thread can be inserted into > the sleepq. The thread would never be woken up. > Has there already been a bug filed for the above issue?
Thanks, -Eric
