Do people that are born in the same place at the same time have the exact
same birth chart in astrology? Do a birth chart, say, yourself, gets
repeated often or is it unique as not repeatable even in a million year? If
so how the west say that combination of planets and starts quoted are
unreliable as getting repetitive? Ganitham is the oldest pride of the
Indian Nation from whom only, the knowledge spread to Greece, Assyria and
Babylonia, but the truth by altering the time lines, of India, pushed up
the age of civilization of less known nations, to prove that India was as;
lagging behind as other nations or other nations of Europe across only were
well learned. Now by that math, your Jadagam may get repeated only after so
many million years; and all the jadagams in permutation and combination
have so many incomprehensible, even the first one has not been released, as
the population OF THE WORLD HAS CROSSED JUST NOT EVEN ONE PERCENT OF THE
JADAGAMS HAT WOULD ARISE CONTINUOUSLY. The doubt may arise that MOON takes
30 days; Saturn 20 years; Jupiter only 12 years; so getting repetitions of
the west must be correct. NO SIR; I mean your chart where 9 planets occupy
12 boxes on that Nano second of your birth time and at a location. Suppose
assume that sun on Mesham, moon on rishabam, mars on mithunam, mercury on
katakam, Guru on simha, sukra in Kanni, Saturn in thulam,rahu 0n vrichikam
and Ketu on rishabam with the ascendant in any one Rasi, getting back the
same position again would take , many million years!!. Shall we see
mathematically with many Ifs AND BUTs?
2 Suppose the same birth timers (KR is that correct or parted by
nano-seconds?) shall have the same Jadagams? No! (KR even a Siamese twins
heads do not appear simultaneously but one after another, parted by Nano
seconds which would expedite the speed of the planets, who will be in 2
different positions in their movements). In January 2001, twin girls were
born 15 seconds apart in an emergency C-section in upstate New York.
Originally, the first baby was thought to be in danger of dying—and she
was. She was out of danger however as soon as they removed the umbilical
cord from around the baby’s neck. The second baby had more serious issues:
All of her organs were reversed. IF she survived the next 48 hours, the
surgical team would begin to plan for what would be the first of many
operations. Well, she did survive those next 48 hours, and that’s how it
happened to get involved to determine the outcome of the first operation.
15 seconds do alter the placements of the Cosmas planets and stars who are
all whirring at such high speeds. In fact, while the first one did things
that brought attention to the health of the second one, each has her own
personality and her own unique life experiences. Their charts are close—but
not precisely the same. The cosmos keeps moving. NASA guesstimates that
movement just fast enough for it to take about 25828 years to recur at the
same place again (KR same as precision according to NASA) —a virtual
impossibility with this kind of precision in such a very short time. [KR
Both will have had similar life patterns with so many different special
characters which is the charm of astrology and that is why we do bring out
the form to fix the future and the features.] The NASA maths was based on
the star’s movements wrt the earth axis wobbling. That is even a star to
touch down the same position ONLY WRT THE EARTH AXIS ITSELF would consume
so many years! So, your star would be seen in every second person you may
meet as only 27 stars are available; but that position of that star at that
position wrt the earth axis, may take 25000 plus years; the star in every
second person is that star moved from place 1 to place 2 to place “n”.
Suppose the 9 planets were to be arranged in the 12 squares, what are the
permutations and combinations to get back the similarity? 1 one
calculation was taken down straight wrt 9 and 12 factorials and 2 the
other, certain conditional formulations were deployed so increase in
variations of permutations and combinations were altered.
you're solving for
1 The number of ways to arrange 9 planets in 12 squares, considering
both permutations and combinations.
What's given in the problem
- Number of squares: 12
- Number of planets: 9
Helpful information
- Permutations consider the order of arrangement.
- Combinations do not consider the order of arrangement.
- The formula for permutations is
nPr=n! (n−r)! sub n cap P sub r equals the fraction with numerator n
exclamation mark and denominator open pare n minus r close pare exclamation
mark end-fraction 𝑛𝑃𝑟=𝑛! (𝑛−𝑟)!
. The formula for combinations is nCr=n! r! (n−r)! sub n cap C sub r equals
the fraction with numerator n exclamation mark and denominator r
exclamation mark open pare n n minus r close pare n exclamation mark
end-fraction
𝑛𝐶𝑟=𝑛!𝑟!(𝑛−𝑟)!
How to solve
First, calculate the number of ways to choose 9 squares out of 12. Then,
calculate the number of ways to arrange the 9 planets in the chosen
squares. Finally, multiply these two results.
*Step 1* . Calculate the number of ways to choose 9 squares out of 12
o Use the combination formula:
§ 12C9=12!9! (12−9)! sub 12 cap C sub 9 equals the fraction with numerator
12 exclamation mark and denominator 9 exclamation mark open pare n 12 minus
9 closes pare n exclamation mark end-fraction
12𝐶9=12!9! (12−9)!
§ 12C9=12!9!3! sub 12 cap C sub 9 equals the fraction with numerator 12
exclamation mark and denominator 9 exclamation mark 3 exclamation mark
end-fraction
12𝐶9=12!9!3!
12C9=12×11×103×2×1sub 12 cap C sub 9 equals the fraction with numerator 12
cross 11 cross 10 and denominator 3 cross 2 cross 1 end-fraction
12𝐶
9=12×11×103×2×1
12C9=220sub 12 cap C sub 9 equals 220
12𝐶9=220
*Step 2* . Calculate the number of ways to arrange 9 planets
§ Use the permutation formula:
9P9=9!(9−9)!sub 9 cap P sub 9 equals the fraction with numerator 9
exclamation mark and denominator open paren 9 minus 9 close paren
exclamation mark end-fraction
9
𝑃9=9!(9−9)!
9P9=9!0!sub 9 cap P sub 9 equals the fraction with numerator 9 exclamation
mark and denominator 0 exclamation mark end-fraction
9𝑃9=9!0!
9P9=9!sub 9 cap P sub 9 equals 9 exclamation mark
9𝑃9=9!
§ 9P9=362880sub 9 cap P sub 9 equals 362880
9𝑃9=362880
*Step 3* . Multiply the results from Step 1 and Step 2
o Total arrangements:
§ 220×362880=79833600220 cross 362880 equals 79833600
220×362880=79833600
Solution There are 9,833,60079 comma 833 comma 600 79,833,600
ways to arrange 9 planets in 12 squares.
*Combinations*
In combinations, the order does not matter, and we are simply choosing 9
houses from 12 for the planets. The formula for combinations is:
C(n,r)=n!r!(n−r)!C(n,r)=n!r!(n−r)!
Here, n=12n=12 (houses) and r=9r=9 (planets):
C(12,9)=12!//9! *(12−9)!
=12! // 9! * 3!
Calculating this:
C(12,9)=479001600 // 362880 * 6
=479001600 // 2177280 =220
*Summary Number of Permutations*: 79,833,600
- * Number of Combinations*: 220
Top of Form
Total Amount in a Set (n)
Amount in each Sub-Set (r)
Bottom of Form
Result
*Permutations*, nPr =
12!
(12 - 9)!
=
*79,833,600*
*Combinations*, nCr =
12!
9! × (12 - 9)!
=
*220*
Xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Part 2 With many conditional alterations the permutational combinations do
increase a lot.
*How many permutations and combinations of occupation of 12 houses by 9
planets may we have in astrology?*
9 planets and 12 houses. However, Rahu and Ketu are the same axis, so
mathematically one can be ascertained from the other and they are not
independent objects to be considered in a permutation. So the two of them
make one single object and thus there are mathematically 8 entities or
objects with which we can make different combinations.
Again, mercury and sun are never more than 20 degrees apart. So let us
consider those as one object as well for now and ignore Mercury. We’ll get
to the finer arrangement later but for now, let us assume them as one
object. So 7 objects as of now.
Now, those 7 objects can be arranged in 12 boxes or houses. Thus, the
possible number of combinations is: 12 to the power of 7 which is roughly
36 million. [127]
Now, these combinations of horoscopes will vary depending on the order of
planets. If Venus is behind Mercury, the results are different, if Venus is
ahead of mercury, the results are different.
So, the 9 planets that we arranged in 12 boxes can be arranged in different
orders for every position we calculated. Like, say one of the combinations
calculated earlier was one planet each from Aries to Libra (Remember we
have taken only 7 planets as of now). Now, this one planet each can also be
arranged differently. We can have the Sun in Aries, the Moon in Taurus,
Mars in Gemini and so on. Or we can have Moon in Aries, Sun in Taurus etc.
Or we can have Mars in Aries, Moon in Taurus and so on. Which means, all
the above combinations can be shuffled and rearranged.
The possible rearrangements are: 7!7! or 7 factorial which equals 5040.
So, the total combinations as of now is (127) ∗ (7!) which is (36M) ∗(5040)
Now, in any sign there are 30 degrees and each of the planets can be in any
of those 30 degrees. So, the various probable combinations are:
(127) ∗ (7!) ∗ (307)
30 to the power 7 is approximately 22
billion.
So as of now, the number of possible combinations
is
(36M)∗(5040)∗(22B)..
Now, remember that we had taken the Sun and ignored Mercury because Mercury
can be anywhere only in plus or minus 20 degrees from the Sun. Which means,
there are 40 different possible positions of Mercury for each position of
Sun. So now let us put Mercury in our equation.
(36M)∗
(5040)∗(22B)∗(40)
Finally, the twelve signs can become different houses or *bhavas *depending
on the ascendant or *lagna.* The ascendant is the degree of the rising sign
in the eastern horizon at any time. It can be anything from 0-degree Aries
to 30 degrees Pisces. Which means, for every given combination calculated
above, there are 360 different combinations of Ascendant. Which means, we
have as our final equation:
(36M)∗(5040)∗(22B)∗
(40)∗(360)
Now, at this point I’ll have to shift to scientific notation to give you an
estimate of how many different horoscopes are possible. So, we have:
(3.6∗107) ∗(5.04∗103) ∗(2.2∗(1010)) ∗40∗360=574801.92 ∗(1020)
=5.75∗(105))∗(1020)
=574801.92∗(10^20)
=5.75∗(10^5))∗(10^20)
*=5.75*(10^25)*
Which is 575 followed by 23 zeroes.
According to an old study based on a lot of approximations, the total
number of humans to have ever been born on earth is 107,602,707,791 or
*(1.07*10^
(11)).*
Now, let us calculate what percentage of available horoscopes has the human
civilization used. This will be given by the simple percentage formula. No.
of humans to have ever been used (No. of horoscopes used) divided by total
no. of horoscopes.
This is: ((1.07∗(1011))/(5.75∗(1025))∗100
=1.8∗(10-13)
Which is *0.00000000000018 % So far the population has used only ,not
even the 1% Jadagam available by permutations and combinations; so your
Jadagam is unique and not even repeated till date. *
So basically, each of the people born on the earth will continue to have
unique lives and destinies till the time life is possible on earth. Our Sun
will burn out much before and life as we know on earth will die before the
number of horoscopes available can be exhausted.
Yes of course there are times when people have coincidences, but they’re
not because of similar horoscopes but becomes of some common pattern that
gets repeated. The entire life* is not, will not, and cannot* be the same.
Also, note that I haven’t yet factored in Uranus, Neptune, Pluto and the 60
minutes that make up a degree which are equally important in defining our
destinies. That would mean that even after 1000 births one soul may not
repeat its old Jadagam as karma rules the roost. Every life may have a few
common things such as appearance but not the same life.
KR IRS 14525
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