*x.transpose(1, 0, 2)* does the trick.
Thank you Fred & Pascal !
On Thursday, August 11, 2016 at 6:53:34 AM UTC+2, Pascal Lamblin wrote:
>
> Check out x.transpose(...), it should work as in numpy if you want to
> test.
>
> On Tue, Aug 02, 2016, Usama Yaseen wrote:
> > I want to re-order elements in 3d lists/tensor3 such that: (python
> version)
> >
> > x_d =
> [[[1,0,0,0],[0,11,0,0],[0,0,111,0]],[[2,0,0,0],[0,22,0,0],[0,0,222,0
> > ]],[[3,0,0,0],[0,33,0,0],[0,0,333,0]]]
> >
> >
> > print(zip(*x_d))
> >
> >
> > [([1, 0, 0, 0], [2, 0, 0, 0], [3, 0, 0, 0]), ([0, 11, 0, 0], [0, 22, 0,
> 0],
> > [0, 33, 0, 0]), ([0, 0, 111, 0], [0, 0, 222, 0], [0, 0, 333, 0])]
> >
> >
> >
> > How can I achieve the same behavior in Theano ?
> >
> >
> >
> > import theano
> > import theano.tensor as T
> >
> >
> > x = T.tensor3('x')
> > f = theano.function([x], ?)
> > x_d =
> [[[1,0,0,0],[0,11,0,0],[0,0,111,0]],[[2,0,0,0],[0,22,0,0],[0,0,222,0
> > ]],[[3,0,0,0],[0,33,0,0],[0,0,333,0]]]
> > print(f(x_d))
> >
> >
> > Thanks !
> >
> > --
> >
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>
> --
> Pascal
>
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