Hi, When we clone a shared variable, it will create a new object. So if you compare them equal, it will be false.
But they will represent the same value under the hood. This mean that if you change the value of one of cloned or the original shared variable. This change will be reflected in the other. Mostly, they have the same ptr to the same data. It is not the same a making 2 shared variable with the same initial value, as in that case, change of values to one ins't replicated to the other. Fred On Wed, Aug 31, 2016 at 1:10 PM, AA <[email protected]> wrote: > According to the documentation, clone has a flag (share_inputs) which, if > set to False, will clone the shared variables in the computational graph. > But what exactly does that mean? > > If I understand correctly, the function returns a symbolic expression > which is identical to the one given as a parameter, except some nodes in > the graph have been replaced. > First of all, how does one reference the other variables that are cloned > if share_inputs is set to False? they don't seem to be part of what > theano.clone returns. > > Second of all, what exactly does it mean to clone a shared variable, when > the underlying storage is the same? how does that affect training? > > Thank you :) > > -- > > --- > You received this message because you are subscribed to the Google Groups > "theano-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > For more options, visit https://groups.google.com/d/optout. > -- --- You received this message because you are subscribed to the Google Groups "theano-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
