The solution is to use and update shared variables instead of returning values. Now I finally understand how Theano works.
On Monday, September 5, 2016 at 12:52:45 AM UTC+2, Kiuhnm Mnhuik wrote: > > I admit I didn't read Theano documentation very thoroughly, because I use > Lasagne and usually I don't need to know Theano very well. > > This time, I'd like to run a function twice and pass its outputs to > another function. In pseudo-code: > > out1 = f(input1) > out2 = f(input2) > result = g(out1, out2) > > I see two sub-optimal solutions: > > - compute out1, read its value, compute out2, read its value and then > pass them to g > - duplicate f (f1 and f2) > > Is there a better solution? > -- --- You received this message because you are subscribed to the Google Groups "theano-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
