Hi,
Theano is a functional programming system. To see only one branch executed,
it must be in the graph. Here is an example with the Print op that have a
printing as a side effect:
import theano.ifelse
import theano.tensor as T
a=theano.shared(2)
b=theano.shared(10)
theano.ifelse.ifelse(T.gt(b,a), theano.printing.Print("T")(a),
theano.printing.Print("F")(b)).eval()
Two thing to remember:
- this op have more overhead then switch. So only try to use it to save
significant computation
- We do not guaranty that the minimal number of node will be executed.
There is interaction with some optimization and if you want to get more
node not executed, you should disable some optimization like using this
flag: "optimizer_exclusing=inplace". Sadly, this disable more then the
minimum of optimization needed. There is no way without significant work to
disable the minimum of optimization.
Fred
On Thu, Dec 14, 2017 at 2:21 PM Ines Ayed <[email protected]> wrote:
> I looked up a theano variant for keras.backend.switch, beause I did not
> want both operations to be executed and I found this :
> https://github.com/Theano/Theano/blob/master/theano/ifelse.py
>
> Here it says that (lazy) ifelse executes only the branch corresponding to
> the condition and not both like switch. I tested it like this:
>
> import theano
>
> def function1():
> print("function 1 is executed")
> return a
>
> def function2():
> print("function 2 is executed")
> return b
> a = 2
> b = 10
> result = theano.ifelse.ifelse(T.gt(b,a), function1(), function2())
>
> But when I run this both messages are printed which means that both
> branches are executed. This is confusing since the description of ifelse
> says that it should not. Am I missing something here?
>
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